Now assume the ball is tossed at a 45¬° angle to the ground with an initial velocity of 9.8m/s.
(4) How long is the ball in the air?
Again, calculate the time to the peak. In this situation, however, the initial velocity has changed. 9.8m/s is now the resultant velocity; the vertical component must be found. Since the ball is thrown at a 45¡ angle, the vertical component equals the magnitude of the resultant divided by Ã2. Therefore, the initial velocity is 6.93m/s.